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Introduction Let G be a finite group and let Irr(G) be the set of irreducible characters of G. We say that an element g in G is a vanishing element if there exists some XE Irr(G) such that x(g) = 0. In this paper, we investigate the influence of the number of the columns containing some zeros in character table of G on the algebraic structure of G. Material and Methods Let Van(G) be the set of all vanishing elements, in other words, Van(G) = {g E G❘ 3χ € Irr(G) X(g) = 0 }. We can easily check that Van(G) is the union of some conjugacy classes. Burnside show that Van(G) = Ø if and only if G is an abelian group. We know that finite groups whose set of vanishing elements is the union of at most three conjugacy classes are solvable. Using this result, we provide a relatively short proof for the main theorem. Results and discussion In this paper, we classify finite groups whose set of vanishing elements is the union of exactly three conjugacy classes. Conclusion If the set of vanishing elements of a finite group G is the union of exactly three conjugacy classes then one of the following,situations:occurs Gis isomorphic to D8, Q8, or S4. G is a Frobenius group with abelian kernel of odd order and cyclic complement of order 4. GFxZ3, in which F is a Frobenius group with abelian kernel of odd order and complement of order 2. [ABSTRACT FROM AUTHOR]