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Further refining swampland dS conjecture in mimetic f(G) gravity.

Authors :
Noori Gashti, S.
Sadeghi, J.
Alipour, M. R.
Source :
International Journal of Modern Physics D: Gravitation, Astrophysics & Cosmology. Feb2023, Vol. 32 Issue 3, p1-21. 21p.
Publication Year :
2023

Abstract

Mimetic gravity analysis has been studied as a theory in various types of general relativity extensions, such as mimetic f (R) gravity, mimetic f (R , T) gravity, mimetic f (R , G) gravity, etc. in the literature. This paper presents a set of equations arising from mimetic conditions and studies cosmic inflation with a combination of mimetic f (G) gravity and swampland dS conjectures. We analyze and evaluate these results. Therefore, we first thoroughly introduce the mimetic f (G) gravity and calculate some cosmological parameters such as the scalar spectral index, the tensor-to-scalar ratio, and the slow-roll parameters. Also, we investigate the potential according to the mimetic f (G) gravity. Then we will challenge the swampland dS conjectures with this condition. By expressing the coefficient of swampland dS conjectures viz C 1 and C 2 in terms of n s and r , we plot some figures and determine the allowable range for each of these cosmological parameters and these coefficients, and finally, compare these results with observable data such as Planck and BICEP2/Keck array data. We show C 1 and C 2 are not (1) , so the refining swampland dS conjecture is not satisfied for this inflationary model. Then we examine it with further refining swampland dS conjecture, which has a series of free parameters such as a , b > 0 , q > 2 and a + b = 1. By adjusting these parameters, the compatibility of the mentioned conjecture with the inflationary model can be discussed. We determine the further refining swampland dS conjecture is satisfied. when a < 1 1. 0 0 4 8 9 = 0. 9 9 5 1 3 , we can always find a , b and q whose value is larger than 2, viz for q = 2. 4 , we find 0. 9 9 1 8 5 ≤ a < 1 , which we can choose a = 0. 9 9 2 3 5 according to the condition a < 0. 9 9 5 1 3. Also we know b = 1 − a , so we will have 1 − 0. 9 9 2 3 5 = 0. 0 0 7 6 5 > 0. [ABSTRACT FROM AUTHOR]

Details

Language :
English
ISSN :
02182718
Volume :
32
Issue :
3
Database :
Academic Search Index
Journal :
International Journal of Modern Physics D: Gravitation, Astrophysics & Cosmology
Publication Type :
Academic Journal
Accession number :
162104252
Full Text :
https://doi.org/10.1142/S0218271823500116