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Is the a[sub 0](1450) a Candidate for the Lowest qq[sup 3]P[sub 0] State?
- Source :
- Physics of Atomic Nuclei; Jul2003, Vol. 66 Issue 7, p1342, 7p
- Publication Year :
- 2003
-
Abstract
- For a[sub 0](1450), considered as the q&qmacr; 1³P[sub 0] state, "experimental" tensor splitting, c[sub exp] = -150 ± 40 MeV, appears to be in contradiction with the conventional theory of fine structure. There is no such discrepancy if a[sub 0](980) belongs to the q&qmacr; 1³P[sub J] multiplet. The hadronic shift of a[sub 0](980) is shown to be greatly dependent on the value of strong coupling in spin-dependent interaction. [ABSTRACT FROM AUTHOR]
- Subjects :
- TENSOR algebra
COUPLING constants
Subjects
Details
- Language :
- English
- ISSN :
- 10637788
- Volume :
- 66
- Issue :
- 7
- Database :
- Complementary Index
- Journal :
- Physics of Atomic Nuclei
- Publication Type :
- Academic Journal
- Accession number :
- 10316074
- Full Text :
- https://doi.org/10.1134/1.1592589