Back to Search Start Over

Is the a[sub 0](1450) a Candidate for the Lowest qq[sup 3]P[sub 0] State?

Authors :
Badalian, A. M.
Source :
Physics of Atomic Nuclei; Jul2003, Vol. 66 Issue 7, p1342, 7p
Publication Year :
2003

Abstract

For a[sub 0](1450), considered as the q&qmacr; 1³P[sub 0] state, "experimental" tensor splitting, c[sub exp] = -150 ± 40 MeV, appears to be in contradiction with the conventional theory of fine structure. There is no such discrepancy if a[sub 0](980) belongs to the q&qmacr; 1³P[sub J] multiplet. The hadronic shift of a[sub 0](980) is shown to be greatly dependent on the value of strong coupling in spin-dependent interaction. [ABSTRACT FROM AUTHOR]

Subjects

Subjects :
TENSOR algebra
COUPLING constants

Details

Language :
English
ISSN :
10637788
Volume :
66
Issue :
7
Database :
Complementary Index
Journal :
Physics of Atomic Nuclei
Publication Type :
Academic Journal
Accession number :
10316074
Full Text :
https://doi.org/10.1134/1.1592589