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Isomorphisms of quadratic quasigroups.
- Source :
- Proceedings of the Edinburgh Mathematical Society; Nov2023, Vol. 66 Issue 4, p1085-1109, 25p
- Publication Year :
- 2023
-
Abstract
- Let $\mathbb F$ be a finite field of odd order and $a,b\in\mathbb F\setminus\{0,1\}$ be such that $\chi(a) = \chi(b)$ and $\chi(1-a)=\chi(1-b)$ , where χ is the extended quadratic character on $\mathbb F$. Let $Q_{a,b}$ be the quasigroup over $\mathbb F$ defined by $(x,y)\mapsto x+a(y-x)$ if $\chi(y-x) \geqslant 0$ , and $(x,y) \mapsto x+b(y-x)$ if $\chi(y-x) = -1$. We show that $Q_{a,b} \cong Q_{c,d}$ if and only if $\{a,b\} = \{\alpha(c),\alpha(d)\}$ for some $\alpha\in \operatorname{Aut}(\mathbb F)$. We also characterize $\operatorname{Aut}(Q_{a,b})$ and exhibit further properties, including establishing when $Q_{a,b}$ is a Steiner quasigroup or is commutative, entropic, left or right distributive, flexible or semisymmetric. In proving our results, we also characterize the minimal subquasigroups of $Q_{a,b}$. [ABSTRACT FROM AUTHOR]
Details
- Language :
- English
- ISSN :
- 00130915
- Volume :
- 66
- Issue :
- 4
- Database :
- Complementary Index
- Journal :
- Proceedings of the Edinburgh Mathematical Society
- Publication Type :
- Academic Journal
- Accession number :
- 174300696
- Full Text :
- https://doi.org/10.1017/S0013091523000585