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A short proof of Grinshpon's theorem
- Publication Year :
- 2009
-
Abstract
- Grinshpon has proved that if $S$ is a commutative subring of a ring $R$ and $A\in M_n(S)$ is invertible in $M_n(R)$, then $det(A)$ is invertible in $R$. We give a very short proof of the result.<br />Comment: 1 page
- Subjects :
- Mathematics - Rings and Algebras
Subjects
Details
- Database :
- arXiv
- Publication Type :
- Report
- Accession number :
- edsarx.0904.0906
- Document Type :
- Working Paper